Find The Domain And Range Of The Function Y 1 2 Sin3x

Then plug that answer into the function to find the range.

Find the domain and range of the function y 1 2 sin3x. Therefore 2 sin3x 0 for all real x. To find the range of a function first find the x value and y value of the vertex using the formula x b 2a. Add to both sides of the inequality.

The denominator is greater than zero for all real x so the domain of the function is all real numbers. Domain range functions even and odd functions. So sin3x belongs to 1 1.

To ask unlimited maths doubts download doubtnut from https goo gl 9wzjcw find the domain and range of the function f x 1 2 sin3x. The domain is all values of that make the expression defined. To properly notate the range write out the numbers in brackets if they re included in the domain or in parenthesis if they re not included in the domain.

I will suppose so. Modification of work by the u s. Click here to get an answer to your question find the domain the range of the function y 1 2 sin3x y 1 2 sin3x.

The sine function is defined over all real numbers so the only remaining concern would be division by zero 1 sin 3x 1 1 sin 3x 1. The input quantity along the horizontal axis is years which we represent with the variable latex t latex for time. Find the domain and range y square root of x 7.

I e f x is defined for all real x. Which means domain of f x is r set of all real no s. Given f x 1 2 sin3x 1 we know sinp belongs to 1 1 for all real p.